Sum of the digits of a number

Description: Write digit_sum(int n). For 9475 the answer is 25.

Hint:

• n % 10 is the last digit, n / 10 removes it.

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Solution

#include <iostream>

int digit_sum(int n) {
    int sum = 0;
    while (n > 0) {
        sum += n % 10;
        n /= 10;
    }
    return sum;
}

int main() {
    std::cout << digit_sum(9475) << ' ' << digit_sum(100) << ' ' << digit_sum(0) << '\n';
}

How it works

• The loop adds the last digit and cuts it off, until the number is 0.

Read C++ while Loop.

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