Write a C program to count the digits in a number

Description: Take a number as input and print how many digits it has.

Hint:

• Divide the number by 10 in a loop, and count how many times you can do it before it becomes 0.

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C program to count the digits of a number

#include <stdio.h>

int main(void) {
    int n, count = 0;

    printf("Enter a number: ");
    scanf("%d", &n);

    if (n == 0) {
        count = 1;
    }
    while (n != 0) {
        n /= 10;
        count++;
    }
    printf("Number of digits = %d\n", count);
    return 0;
}

Output:

How it works

• 45678 becomes 4567, 456, 45, 4 and finally 0. That is 5 divisions, so 5 digits.
• The number 0 has one digit, so we handle it separately.

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